Vedic maths: Square
Example : Find square of 12
Step 1
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The deviation to our base =12−10=2=12−10=2 (To find the deviation, just remove the leftmost digit “11” and you will get it quickly).
Left side of the answer is the sum of the number and deviation. Hence, left side of the answer = 12 + 2 = 14
Step 2
Our base 1010 has a single zero. Therefore, right side of the answer has a single digit and that can be obtained by taking the square of the deviation.
Hence, right side of the answer =22=4=22=4
Therefore, answer =144
Vedic maths: Square roots
Square root of any number means to get a number which is multiplied by itself gives the given number. In the conventional method of finding the square root, the divisor goes on becoming larger at each step. This increases the calculation time as well as the complexity of the problem. Here, we shall try to learn some speedy Vedic Methods of finding the square roots of perfect square numbers. Before proceeding for finding square roots, let us have a look into the known facts of squares and square roots.
The basic rules for extracting square roots are :
1² = 1, 2²=4 , 3²=9 , 4²=16 , 5²=25, 6²=36, 7²=49, 8²=64 , 9²=81
This means :
Unit digit of the number 1 4 5 6 9 0
Unit digit of square root 1 or 9 2 or 8 5 4 or 6 3 or 7 0
Cube roots in vedic maths
Find Cube Root of 4913
Step 1
Identify the last three digits and make groups of three three digits from right side. i.e., 49134913 can be written as
4, 913
Step 2
Take the last group which is 913.913. The last digit of 913913 is 3.3.
Remember point 2, If last digit of perfect cube=3,=3, last digit of cube root =7=7
Hence the right most digit of the cube root =7
Step 3
Take the next group which is 44
Find out which maximum cube we can subtract from 44 such that the result ≥0≥0
We can subtract 1 3 = 1 from 4 because 4 − 1 = 3 (If we subtract 2 3 = 8 from 4 , 4 – 8 = − 4 which is < 0 )
Hence the left neighbor digit of the answer = 1 i.e., answer = 17